/*
# 问题分析
题目要求给出冠军队伍的编号和总成绩。这是一道统计题(统计各队伍分数)/最值题(分数最高)
这类题目已经出现多次, 主要思路为: 统计各个队伍分数后对统计结果进行比较求最值。
 
# 完整描述步骤
1. 获取输入: 各个队伍的信息（队伍编号、队员编号、成绩）
2. 对于每一个队伍的数据:
    - 将队员的成绩加到对应队伍的总分中
    - 检查当前队伍加分后的成绩与记录的最高分的大小情况
        - 如果大于当前记录的最高分, 则更新最高分和队伍编号
3. 输出最高分队伍编号和成绩
 
# 伪代码描述
1. get input: player_amount, player_info(team_num, player_num, player_score)
2. init counter: 
    - team_scores[10001] = {0}
    - max_score_team_num = -1
    - max_score_team_score = 0
3. for each player info:
    - team_scores[team_num] += player_score
    - if team_scores[team_num] > max_score_team_score:
        - max_score_team_score = team_scores[team_num]
        - max_score_team_num = team_num
4. print(max_score_team_num, max_score_team_score)
*/
 
# include<stdio.h>
 
int main() {
  int player_amount;
  scanf("%d", &player_amount);
  int team_scores[1001] = {0};
 
  int team_num, player_num, player_score;
  int max_score_team_num = 0, max_score_team_score = 0;
  for (int i = 0; i < player_amount; i++) {
    scanf("%d-%d %d", &team_num, &player_num, &player_score);
    team_scores[team_num] += player_score;
    if (team_scores[team_num] > max_score_team_score) {
      max_score_team_score = team_scores[team_num];
      max_score_team_num = team_num;
    }
  }
 
  printf("%d %d", max_score_team_num, max_score_team_score);
  return 0;
}